# coding: utf-8

# # [Project Euler](https://ProjectEuler.net)
# [This Python 3 notebook](Project%20Euler%20%28Python%203%29.ipynb) contains *some* solutions for the [Project Euler](https://ProjectEuler.net) challenge.
# 
# ### /!\ **Warning:** do not spoil yourself the pleasure of solving these problems by yourself!
# 
# [I (Lilian Besson)](http://perso.crans.org/besson/) started in February 2015, and worked occasionally on Project Euler problems in March and April 2015.
# I should try to work on it again, hence this notebook...
# 
# ![Badge giving the number of solved problems](https://ProjectEuler.net/profile/Naereen.png "Badge giving the number of solved problems")

# ----
# 
# ## Problem 32 : Pandigital products
# *Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital.*

# In[6]:

maxN = 987654321
maxN = 654321  # XXX Passer à la vraie valeur
l = len(str(maxN))
sum32 = 0
digits19 = set(range(1, l+1))
for multiplicand in range(1, 1+maxN):  # upto 987 654 321
    multiplier = 1
    product = multiplicand * multiplier
    while multiplier <= maxN and product <= maxN:  # Be smart here!
        digits = str(multiplicand)+str(multiplier)+str(product)
        if len(digits) == l and set(digits) == digits19:
            print("multiplicand = {}, multiplier = {}, product = {}".format(multiplicand, multiplier, product))
            print("digits =", digits)
            sum32 += product
        multiplier += 1
        product = multiplicand * multiplier

print("The sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through", l, "pandigital is")
print(sum32)


# In[ ]: